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Journal of Pure and Applied Mathematics

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Tai-Choon Yoon*
 
Department of Applied Mathematics, Yonsei University, South Korea, Email: tcyoon@hanmail.net
 
*Correspondence: Tai-Choon Yoon, Department of Applied Mathematics, Yonsei University, South Korea, Email: tcyoon@hanmail.net

Received: 15-Aug-2025, Manuscript No. PULJPAM-23-6663; Editor assigned: 17-Aug-2025, Pre QC No. PULJPAM-23-6663 (PQ); Reviewed: 30-Aug-2023 QC No. PULJPAM-23-6663; Revised: 24-Jan-2025, Manuscript No. PULJPAM-23-6663 (R); Published: 31-Jan-2025

Citation: Yoon TC. A compact solution of a cubic equation. J Pure Appl Math. 2025;9(1):1-4.

This open-access article is distributed under the terms of the Creative Commons Attribution Non-Commercial License (CC BY-NC) (http://creativecommons.org/licenses/by-nc/4.0/), which permits reuse, distribution and reproduction of the article, provided that the original work is properly cited and the reuse is restricted to noncommercial purposes. For commercial reuse, contact reprints@pulsus.com

About the Study

In this article, a simple solution of cubic equation is presented by the use of a new substitution

equation

Which can replace a complicated solution presented by G. Cardano, and Francois Viete’s Vieta substitution? This paper also shows that one of the existing solution of the trigonometric function is to be changed to -cos(ÃÃÃÂ??ÂÃÂ??- π/3) instead of cos(ÃÃÃÂ??ÂÃÂ??-4π/3) due to the range limit of the inverse trigonometric function [1].

Derivation of a compact solution of a cubic equation

The solution of cubic equations is well known since an Italian mathematician Gerolamo Cardano had established. In order to replace G. Cardano's solution, I hereby settle a simple and compact substitution for an easier solution [2].

A general form of cubic equations is written as,

equation

Then, a simplified equation divided both sides by the coefficient a is given as,

equation

Substituting x=y-b/3a by using the Tschirnhaus transformation, we get Cardano’s basic form [3]:

equation

Here the coefficients s and t represent respectively.

Cardano’s basic form is:

equation

Cardano’s substitution is

equation

where y=(u+v) is a root of the given cubic equation.

equation

A solution of the cubic equation 1 obtained by Cardano is quite complicated because it needs several steps to get solutions. For a simplified solution, I define a new substitution analogous to Vieta's substitution, which is basically similar to Vieta’s, as is given in the form,

equation

Vieta's solution of a cubic is read as follows:

equation

And the substitution is

equation

which provides

equation

It is to be noted that this substitution provides only one solution of a cubic equation, while Cardano's and Vieta's provide three solutions. By using this substitution, we get from the equation (3),

equation

Multiplying both sides by alpha, we get a quadratic equation,

equation

And, then we get a pair of solutions

equation

Though the resolvent quadratic equation (7) provides two roots as per the above, we can identify that they produce only one radical of the reduced cubic form (3). Substituting each α of (8) respectively, then we find the same result as follows

equation

With this result, we can get the two remaining solutions by letting the above solution as y= y1 and solving the factorized quadratic equation of the right hand side

equation

From this, we get

equation

The discriminant of the cubic is given as

equation

These three roots, (9) and (11) are the solutions of a cubic equation in terms of two unknown coefficients, s and t.

In case the discriminant D>0, of a cubic equation, the roots of (9) and (11) can be used as they are, because the cubic equation has one real roots and two complex conjugate. However, in case of D<0, the value in the square root of (9) is changed to an imaginary unit, in which case, it is convenient to use trigonometric functions,

equation

In case D<0,we may eliminate the imaginary unit by using the trigonometric functions, so we can define an intermediary coefficient θ as follows,

equation

 

where θ is given as

equation

By substituting the above into the equation (9), we get the following result by using the de Moivre’s formula [4]

de Moivre’s formula proves that cosnx +isinnx = (cosx+i sinx )n.

equation

Where i represents the imaginary unit.

And the remaining two roots are given from the equation (11)

equation

with θ[2] of (14).

The three real roots of a depressed form (t^3+pt+q=0) can be expressed as

equation

As the results, in case that the discriminant of the cubic equation (3) is D<0, the three real roots of (15) and (16) can be expressed as an inverse function of trigonometry as follows,

equation

A generalized solution of a cubic equation

A general form of a cubic equation

equation

Dividing by the leading coefficient a, we get a monic cubic equation

equation

A depressed form of the above by substituting with x=y-b/3a, we get

equation

Where

equation

From the above (19), we get a solution of a cubic,

equation

where D3 is the discriminant of a cubic equation given as

equation

and the remaining two roots are

equation

As the results, a solution of the cubic equation (18) is given as,

equation

and the remaining two solutions,

equation

with D3 of (22).In case D3>0, the cubic equation has one real root of (24) and two complex conjugate of (25).

In case D3=0, it has three real roots, two of which are equal to each other.

If D3<0, the cubic has three different real roots.

References

 
Google Scholar citation report
Citations : 83

Journal of Pure and Applied Mathematics received 83 citations as per Google Scholar report

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